IDZ 10.2 - Option 14. Decisions Ryabushko AP
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- Find the equation of the tangent plane and the normal to the given surface S at the point M0 (x0, y0, z0)
1.14 S: x2 - 2y2 + z2 + xz - 4y = 13, M0 (3, 1, 2)
- Find the second partial derivatives of the functions. Ensure that z "xy = z" yx
2.14 z = cos (x2y2 - 5)
- To verify whether the above equation the function u.
- Examine the following function extremum.
4.14 z = x3 + y3 - 3xy
- Find the maximum and minimum values of the function z = z (x, y) in D, given the limited lines.
5.14 z = 2x2 + 3y2 + 1, D: y = √9-9 / 4x2, y = 0
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