IDZ 10.2 - Option 19. Decisions Ryabushko AP
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- Find the equation of the tangent plane and the normal to the given surface S at the point M0 (x0, y0, z0)
1.19 S: x2 + y2 - z2 + xz + 4y = 4, M0 (1, 1, 2)
- Find the second partial derivatives of the functions. Ensure that z "xy = z" yx
2.19 z = arctg (2x - y)
- To verify whether the above equation the function u.
- Examine the following function extremum.
4.19 z = xy - x2 - y2 + 9
- Find the maximum and minimum values \u200b\u200bof the function z = z (x, y) in D, given the limited lines.
5.19 z = xy - 3x - 2y, D: x = 0, x = 4, y = 0, y = 4
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