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IDZ 10.2 - Option 24. Decisions Ryabushko AP

IDZ 10.2 - Option 24. Decisions Ryabushko AP

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  • Find the equation of the tangent plane and the normal to the given surface S at the point M0 (x0, y0, z0)

1.24 S: x2 + y2 - 3z2 + xy = -2z, M0 (1, 0, 1)

  • Find the second partial derivatives of the functions. Ensure that z "xy = z" yx

2.24 z = sin√xy

  • To verify whether the above equation the function u.
  • Examine the following function extremum.

4.24 z = xy (6 - x - y)

  • Find the maximum and minimum values of the function z = z (x, y) in D, given the limited lines.

5.24 z = x2 + 2xy - y2 - 4x, D: x = 3, y = 0, y = x + 1

Additional information

Detailed solution. Designed in PDF format for easy viewing of IDZ solutions on smartphones and PCs. In MS Word (doc format) sent additionally.