IDZ 10.2 - Option 30. Decisions Ryabushko AP
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- Find the equation of the tangent plane and the normal to the given surface S at the point M0 (x0, y0, z0)
1.30 S: z = 2x2 - 3y2 + xy + 3x + 1, M0 (1, -1, 2)
- Find the second partial derivatives of the functions. Ensure that z "xy = z" yx
2.30 z = tg (xy2)
- To verify whether the above equation the function u.
- Examine the following function extremum.
4.30 z = 2 (x + y) - x2 - y2
- Find the maximum and minimum values of the function z = z (x, y) in D, given the limited lines.
5.30 z = 2x2y - x3y - x2y2, D: x = 0, y = 0, x + y = 6
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