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DHS 15.1 - Option 2. Decisions Ryabushko AP

DHS 15.1 - Option 2. Decisions Ryabushko AP

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  • Dana function u (M) = u (x, y, z) and the point M1, M2. Calculate: 1) The derivative of this function in the direction of the point M1 M1M2 vector; 2) grad u (M1)

1.2. u (M) = 5xy3z2, M1 (2, 1, -1), M2 (4, -3, 0)

  • Calculate the surface integral of the first kind on the surface S, where S - part of the plane (p), cut off by the coordinate planes.

(P): 2x - y - 2z = -2

  • Calculate the surface integral of the second kind.

where S - the outer side surface of the ellipsoid x2 + y2 + 2z2 = 2

  • Calculate the flow vector field a (M) through the outer surface of the pyramid formed by plane (p) and the coordinate planes in two ways: a) determination using flow; b) using the formula Ostrogradskii - Gauss.

4.2. and (M) = (3x - 1) i + (y - x + z) j + 4zk, (p): 2x - y - 2z = 2

Additional information

Detailed solution. Designed in PDF format for easy viewing of IDZ solutions on smartphones and PCs. In MS Word (doc format) sent additionally.