DHS 15.1 - Option 26. Decisions Ryabushko AP

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• Dana function u (M) = u (x, y, z) and the point M1, M2. Calculate: 1) The derivative of this function in the direction of the point M1 M1M2 vector; 2) grad u (M1)

1.26. u (M) = ln (1 + x2 - y2 + z2), M1 (1, 1, 1), M2 (5, -4, 8)

• Calculate the surface integral of the first kind on the surface S, where S - part of the plane (p), cut off by the coordinate planes.

(P): x + 2y + 2z = 2

• Calculate the surface integral of the second kind.

where S - the inner side of the closed surface formed by the cone x2 = y2 + z2 and the plane x = 1.

• Calculate the flow vector field a (M) through the outer surface of the pyramid formed by plane (p) and the coordinate planes in two ways: a) determination using flow; b) using the formula Ostrogradskii - Gauss.

4.26. and (M) = (y + z) i + (x + 6y) j + yk, (p): x + 2y + 2z = 2

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