DHS 15.2 - Option 12. Decisions Ryabushko AP

Product description

• Calculate and circulation of the vector field (M) over the contour of a triangle obtained by intersection of the plane (p): Ax + By + Cz = D with the coordinate planes, with respect to the positive direction of the normal vector bypass n = (A, B, C) this plane in two ways: 1) using the definition of circulation; 2) using the Stokes formula.

1.12. a (M) = (2x - z) i + (y - x) j + (x + 2z) k, (p): x - y + z = 2

• Find the magnitude and direction of the greatest changes in the function u (M) = u (x, y, z) at the point M0 (x0, y0, z0)

2.12. u (M) = x2yz, M0 (1, -1, 1)

• Find the greatest density of the circulation of the vector field a (M) = (x, y, z) at the point M0 (x0, y0, z0)

3.12. a (M) = xyi - xy2j - xy2j + z2k, M0 (1, -1, 1)

• Determine whether the vector field a (M) = (x, y, z) the potential

4.12. a (M) = (yz - 2x) i + (xz + zy) j + xyk

Additional information

Detailed solution. Designed in PDF format for easy viewing of IDZ solutions on smartphones and PCs. In MS Word (doc format) sent additionally.