DHS 16.2 - Option 11. Decisions Ryabushko AP
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Product description
- Solve a linear differential equation using the operator method
αẍ + βẋ + γx = f(t), x(t0) = A, ẋ(t0) = B
The function f(t) and values of coefficients α, β, γ, t0, x(t0), ẋ(t0) are taken from the table. 16.4
1.11. α = 1, β = 0, γ = 9, f(t) = 18e3t, t0 = 0, x(t0) = 0, ẋ(t0) = 0
1.11. ẍ + 9x = 18e3t, x(0) = 0, ẋ(0) = 0
- Solve the system of linear differential equations by the operator method
Table of functions f1(t), f2(t) and values ak, bk, ck, dk (k=1, 2), A, B, x(0), y(0). 16.5
2.11. a1 = 3, b1 = 1, c1 = 2, d1 = 0, f1(t) = 1, a2 = 1, b2 = 4, c2 = 0, d2 = 3, f2(t) = 0, x(0) = 0, y(0)=0
Additional information
Detailed solution. Designed in PDF format for easy viewing of IDZ solutions on smartphones and PCs. In MS Word (doc format) sent additionally.