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Solution of problem N3914 probability theory

Solution of problem N3914 probability theory

Seller: Massimo86

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Product description

  • On three machines under the same and independent conditions, parts of the same name are manufactured. On the first machine is made 10%, on the second - 30%, and on the third 60% of all parts. For each part, the probability of being faultless is 0.7 if it is made on the first machine; 0.8, if it is made on the second machine; 0.9 if it is made on the third machine. Find the probability that a part taken at random will be defect free.

Additional information

Detailed solution. Decorated in Microsoft Word 2003 (Quest decided to use the formula editor)