144. Solving a chemistry problem
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6.35. Using the benzene adsorption isotherm, determine the specific surface area of the adsorbent (Т = 293 K, S0 = 49 * 10–20 m2):
P / Ps 0.06 0.10 0.15 0.20 0.25 0.30
A, mol / kg 0.26 0.35 0.43 0.50 0.56 0.63