144. Solving a chemistry problem
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6.26. Using the nitrogen adsorption isotherm, determine the specific surface of the adsorbent (T = 77 K, S0 = 16.2 * 10–20 m2):
P / Ps 0.04 0.09 0.16 0.20 0.30
A, mol / kg 2.20 2.62 2.94 3.11 3.58