143. Solving a chemistry problem
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6.38. Using the benzene adsorption isotherm, determine the specific surface area of the adsorbent (T = 293 K, S0
= 49 * 10–20 m2). The volume of adsorbed gas is reduced to normal conditions:
P / Ps 0.10 0.15 0.20 0.25 0.35 0.40
A * 102, m3 / kg 1.15 1.37 1.55 1.71 1.86 1.99
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