137. Solving a chemistry problem
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Product description
- Calculate the entropy of the reaction CaCO3 (cr) → CaO (cr) CO2 (g) at temperatures of 298.15 and 1200 K, using the absolute entropy of the compounds at T = 298.15 and p = 1 atm: S0CaO = 38.07 J / mol ∙ K, S0CO2 = 213.66 J / mol ∙ K, S0CaCO3 = 91.71 J / mol ∙ K. The dependence of the heat capacity of compounds on temperature is as follows:
Ср (CaO) = 〖49.62 4.52 ∙ 10〗 ^ (- 3) T-6.95 ∙ 〖10〗 ^ 5 T ^ (- 2) J / mol ∙ K
Ср (CO2) = 〖44.14 9.04 ∙ 10〗 ^ (- 3) T-8.54 ∙ 〖10〗 ^ 5 T ^ (- 2) J / mol ∙ K
Ср (CaCO3) = 〖104.52 21.92 ∙ 10〗 ^ (- 3) T-25.94 ∙ 〖10〗 ^ 5 T ^ (- 2) J / mol ∙ K