97. Solving a chemistry problem
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Product description
The potential of a lead selective electrode in a 0.0003 M lead nitrate solution is 86 mV. Calculate the electrode potential in a 0.0018 M solution of the same salt if the slope of the electrode function is 2 mV greater than the theoretical value. How will the potential of the electrode change if the addition of zinc ions to a concentration of 0.00022 M is introduced into this solution. The selectivity coefficient is K (Pb / Zn) \u003d 0.0011.
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