94. Solving a chemistry problem
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Product description
- Draw a diagram of the element with aZn2 =10-2 mol/l at one electrode and aZn2 =10-6 mol/l at the other electrode. Indicate which of the electrodes will be the anode and which will be the cathode. Calculate the EMF of the element.
Additional information
If you do not open the file - install the RAR archiver. Inside the archive you will find a solution in Word format.