88. Solving a chemistry problem
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Product description
- EMF of a galvanic cell
Pt, H2 | 1n CH3COOH || 0.5N HCOOH | H2, Pt at 250C is 20.65 mV. KCH3COOH=1.76*10-5. Define KHCOOH. Answer: 1.76 * 10-4.
Additional information
If you do not open the file - install the RAR archiver. Inside the archive you will find a solution in Word format.