0732. Solving a chemistry problem
Seller: Derkach
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Product description
- Calculate the emf of the cell Pt(t) | Pb(t)| PbI2(s) | HI(aq)| H2(r)| Pt(s) with activity HI(aq) equal to 0.815 and hydrogen fugacity 1 atm, knowing the standard electrode potential –0.364 V reaction PbI2(s) 2e– = 2I–(aq) Pb(s), at 25 °C.
Additional information
If you do not open the file - install the RAR archiver. Inside the archive you will find a solution in Word format.