Task id9734
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Product description
X-ray photon energy E = 0.3 MeV. The photon was scattered upon collision with a free resting electron, as a result of which its wavelength increased by Δλ = 0.0025 nm. Determine: the energy of the scattered photon; the angle at which the recoil electron was emitted; kinetic energy of the recoil electron. The speed of light in vacuum is c = 3 • 108 m/s. Planck's constant h = 6.63 • 10-34 J • s. Electron rest energy E0 = mec2 = 0.511 MeV (1 MeV = 1.6 • 10-13 J).
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Detailed solution. Format png