48. Solution to Chemistry Problem
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3.20 For the reaction occurring in a galvanic cell
Pb Hg2Cl2=PbCl2 2Hg E=0.5353 1.45*10-4t. Calculate at 298 K E, ΔG, ΔH and the heat of the reversible process. Compare ΔH with that calculated from the heat of formation. Consist of a galvanic cell, write down the reactions occurring on the electrodes.
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